-2x^2+15x+4=0

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Solution for -2x^2+15x+4=0 equation:



-2x^2+15x+4=0
a = -2; b = 15; c = +4;
Δ = b2-4ac
Δ = 152-4·(-2)·4
Δ = 257
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-\sqrt{257}}{2*-2}=\frac{-15-\sqrt{257}}{-4} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+\sqrt{257}}{2*-2}=\frac{-15+\sqrt{257}}{-4} $

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